Extra Information on the Graphical Analysis Near the
End of Chapter 14
The graphical approach begins with the juvenile survival
curve shown in Figure 14.11 of the book. Juvenile loss is the only loss
in the model that depends on density. All other losses may be combined in
a single line whose slope varies with changes in the harvesting fraction.
Figure 14.11demonstrates with four lines corresponding to harvest fractions
of 0%, 50%, 75% and 90%. The fact that the straight lines intersect the
survival curve is a sign that the harvest fraction is sustainable.

Figure 14.11 (in book) Graphical analysis of the number of smolts and fry
in a sustainable system with different values of the harvest fraction.
To demonstrate, algebraically, why this is true, it is helpful to define the following terms:
| h = harvest fraction | x1 = 25% adult migration loss fraction |
| A = adults arrive at Columbia | x2 = 50% egg loss fraction |
| H = harvest | x3 = 90% smolt loss fraction |
| F = emergent fry | x4 = 35% ocean loss fraction in 1st year |
| S = smolts ready to migrate | x5 = 10% ocean loss fraction in 2nd year |
| ff = 50% fraction female | epr = 3.9 thousand eggs per redd |
This gives the fry, F, as a function of A, the number of
adults. If we happen to know S,
the number of smolts to begin the spring migration, we could find A as follows:
A = S (1-x3) (1-x4) (1-x5) = S (.0585)
Now, insert the expression for A into the previous expression
for F to obtain:
F = S (.0585) (1-h) (.73) or
F = S (.0427) (1-h)
At this point, we have F as a linear function of S. But
you can see from Figure 14.11, that we need to express S as a linear function
of F. This may be done as follows:
S = 23 F/(1-h)
For any value of h, we can express S as a linear function
of F, as shown by the four lines in Figure 14.11. Recall that the purpose
is to find where the four lines intersect the nonlinear curve. These intersection
points reveal the number of fry and the number of smolts that are consistent
with all the assumptions of the model andare consistent with the assumption
that the harvest is sustainable. With 50% harvesting, for example, the intersection
point shows around 8 million fry and around 360,000 smolts. (These values
agree with the values shown in chapter 14.) Now, to find the annual harvest,
we set
H = hA,
and we express A as proportional to S using the previous
expression:
A = S (.0585)
Now suppose we find S from the intersection points in Figure
14.11. We could calculate the annual harvest as:
H = .0585*h*S
Taking the three lines in Figure 14.11 as illustrative,
we could eyeball the value of S to obtain rough approximations to the annual
harvest as follows:
| h | S | H = .0585*h*S |
| 50% | 380,000 | 11,000 |
| 75% | 330,000 | 14,000 |
| 90% | 220,000 | 11,500 |
These values for H, the annual harvest, confirm the two findings from Figure 14.10. That is:
1) the maximum sustainable yield is around 14,000 salmon/yr, and
2) it is possible to obtain yields of over 10,000 salmon/yr
with harvest fractions ranging anywhere from 50% to 90%.